![]() ![]() Raise ValueError('Cannot populate a doubly linked list from an empty set. Iteratively populate the doubly linked list from a set of values # then set the previous node to the current node for the next iterationĬlass DoublyLinkedListNode(LinkedListNode):ĭef _init_(self, val=None, prev=None, next=None): Health and Safety Management professional, Financial Analyst. Website Designer, Graphics designer (logos). # otherwise we link the previous node to the current node Aspiring Software Engineer studying Software Engineering with HyperionDev. # set the head of the SLL on the first pass through the set Node_curr = LinkedListNode(val = set_to_use) # then iterate through to the end of the set, linking each node to the next ![]() Raise ValueError('Cannot start a singly linked list from an empty set.') Iteratively populate a singly linked list from a set of values Print linked list element starting from the head, walkingĭef populate_from_set(self, set_to_use: set): In case it helps anyone, here is an example for converting a set (could be a list or array etc.some sequence) to a singly linked list or a doubly linked list: class LinkedList: """ Below are taken from sample in function prototype comments Return first + ' ' + helper(link.rest) # <<<< RECURSIVE Return Link(lst, list_to_link(lst)) # ' # <<<< RECURSIVE """Takes a Python list and returns a Link with the same elements. Try it out: class Link:Īssert rest is Link.empty or isinstance(rest, Link) It's more about understanding how to write elegant recursive code more than creating linked-list in Python (not really useful or common). This is a pretty standard recursive algorithm introduction. Reading the abstract/prototype, it looks like the creator of the problem wanted to solve this with recursive/dynamic programming methodology. Matt's answer is good, but it's outside the constraint of the function prototype described in the problem above. ![]()
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